Optimal. Leaf size=197 \[ -\frac{8 a^2 \cos (e+f x)}{3 f \sqrt{a \sin (e+f x)+a}}+\frac{29 a^2 \cot (e+f x)}{24 f \sqrt{a \sin (e+f x)+a}}+\frac{37 a^{3/2} \tanh ^{-1}\left (\frac{\sqrt{a} \cos (e+f x)}{\sqrt{a \sin (e+f x)+a}}\right )}{8 f}-\frac{2 a \cos (e+f x) \sqrt{a \sin (e+f x)+a}}{3 f}-\frac{\cot (e+f x) \csc ^2(e+f x) (a \sin (e+f x)+a)^{3/2}}{3 f}-\frac{a \cot (e+f x) \csc (e+f x) \sqrt{a \sin (e+f x)+a}}{4 f} \]
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Rubi [A] time = 0.496362, antiderivative size = 197, normalized size of antiderivative = 1., number of steps used = 8, number of rules used = 8, integrand size = 23, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.348, Rules used = {2718, 2647, 2646, 3044, 2975, 2980, 2773, 206} \[ -\frac{8 a^2 \cos (e+f x)}{3 f \sqrt{a \sin (e+f x)+a}}+\frac{29 a^2 \cot (e+f x)}{24 f \sqrt{a \sin (e+f x)+a}}+\frac{37 a^{3/2} \tanh ^{-1}\left (\frac{\sqrt{a} \cos (e+f x)}{\sqrt{a \sin (e+f x)+a}}\right )}{8 f}-\frac{2 a \cos (e+f x) \sqrt{a \sin (e+f x)+a}}{3 f}-\frac{\cot (e+f x) \csc ^2(e+f x) (a \sin (e+f x)+a)^{3/2}}{3 f}-\frac{a \cot (e+f x) \csc (e+f x) \sqrt{a \sin (e+f x)+a}}{4 f} \]
Antiderivative was successfully verified.
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Rule 2718
Rule 2647
Rule 2646
Rule 3044
Rule 2975
Rule 2980
Rule 2773
Rule 206
Rubi steps
\begin{align*} \int \cot ^4(e+f x) (a+a \sin (e+f x))^{3/2} \, dx &=\int (a+a \sin (e+f x))^{3/2} \, dx+\int \csc ^4(e+f x) (a+a \sin (e+f x))^{3/2} \left (1-2 \sin ^2(e+f x)\right ) \, dx\\ &=-\frac{2 a \cos (e+f x) \sqrt{a+a \sin (e+f x)}}{3 f}-\frac{\cot (e+f x) \csc ^2(e+f x) (a+a \sin (e+f x))^{3/2}}{3 f}+\frac{\int \csc ^3(e+f x) \left (\frac{3 a}{2}-\frac{11}{2} a \sin (e+f x)\right ) (a+a \sin (e+f x))^{3/2} \, dx}{3 a}+\frac{1}{3} (4 a) \int \sqrt{a+a \sin (e+f x)} \, dx\\ &=-\frac{8 a^2 \cos (e+f x)}{3 f \sqrt{a+a \sin (e+f x)}}-\frac{2 a \cos (e+f x) \sqrt{a+a \sin (e+f x)}}{3 f}-\frac{a \cot (e+f x) \csc (e+f x) \sqrt{a+a \sin (e+f x)}}{4 f}-\frac{\cot (e+f x) \csc ^2(e+f x) (a+a \sin (e+f x))^{3/2}}{3 f}+\frac{\int \csc ^2(e+f x) \sqrt{a+a \sin (e+f x)} \left (-\frac{29 a^2}{4}-\frac{41}{4} a^2 \sin (e+f x)\right ) \, dx}{6 a}\\ &=-\frac{8 a^2 \cos (e+f x)}{3 f \sqrt{a+a \sin (e+f x)}}+\frac{29 a^2 \cot (e+f x)}{24 f \sqrt{a+a \sin (e+f x)}}-\frac{2 a \cos (e+f x) \sqrt{a+a \sin (e+f x)}}{3 f}-\frac{a \cot (e+f x) \csc (e+f x) \sqrt{a+a \sin (e+f x)}}{4 f}-\frac{\cot (e+f x) \csc ^2(e+f x) (a+a \sin (e+f x))^{3/2}}{3 f}-\frac{1}{16} (37 a) \int \csc (e+f x) \sqrt{a+a \sin (e+f x)} \, dx\\ &=-\frac{8 a^2 \cos (e+f x)}{3 f \sqrt{a+a \sin (e+f x)}}+\frac{29 a^2 \cot (e+f x)}{24 f \sqrt{a+a \sin (e+f x)}}-\frac{2 a \cos (e+f x) \sqrt{a+a \sin (e+f x)}}{3 f}-\frac{a \cot (e+f x) \csc (e+f x) \sqrt{a+a \sin (e+f x)}}{4 f}-\frac{\cot (e+f x) \csc ^2(e+f x) (a+a \sin (e+f x))^{3/2}}{3 f}+\frac{\left (37 a^2\right ) \operatorname{Subst}\left (\int \frac{1}{a-x^2} \, dx,x,\frac{a \cos (e+f x)}{\sqrt{a+a \sin (e+f x)}}\right )}{8 f}\\ &=\frac{37 a^{3/2} \tanh ^{-1}\left (\frac{\sqrt{a} \cos (e+f x)}{\sqrt{a+a \sin (e+f x)}}\right )}{8 f}-\frac{8 a^2 \cos (e+f x)}{3 f \sqrt{a+a \sin (e+f x)}}+\frac{29 a^2 \cot (e+f x)}{24 f \sqrt{a+a \sin (e+f x)}}-\frac{2 a \cos (e+f x) \sqrt{a+a \sin (e+f x)}}{3 f}-\frac{a \cot (e+f x) \csc (e+f x) \sqrt{a+a \sin (e+f x)}}{4 f}-\frac{\cot (e+f x) \csc ^2(e+f x) (a+a \sin (e+f x))^{3/2}}{3 f}\\ \end{align*}
Mathematica [A] time = 1.35636, size = 334, normalized size = 1.7 \[ -\frac{a \csc ^{10}\left (\frac{1}{2} (e+f x)\right ) \sqrt{a (\sin (e+f x)+1)} \left (276 \sin \left (\frac{1}{2} (e+f x)\right )+326 \sin \left (\frac{3}{2} (e+f x)\right )-78 \sin \left (\frac{5}{2} (e+f x)\right )-72 \sin \left (\frac{7}{2} (e+f x)\right )-8 \sin \left (\frac{9}{2} (e+f x)\right )-276 \cos \left (\frac{1}{2} (e+f x)\right )+326 \cos \left (\frac{3}{2} (e+f x)\right )+78 \cos \left (\frac{5}{2} (e+f x)\right )-72 \cos \left (\frac{7}{2} (e+f x)\right )+8 \cos \left (\frac{9}{2} (e+f x)\right )-333 \sin (e+f x) \log \left (-\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )+1\right )+333 \sin (e+f x) \log \left (\sin \left (\frac{1}{2} (e+f x)\right )-\cos \left (\frac{1}{2} (e+f x)\right )+1\right )+111 \sin (3 (e+f x)) \log \left (-\sin \left (\frac{1}{2} (e+f x)\right )+\cos \left (\frac{1}{2} (e+f x)\right )+1\right )-111 \sin (3 (e+f x)) \log \left (\sin \left (\frac{1}{2} (e+f x)\right )-\cos \left (\frac{1}{2} (e+f x)\right )+1\right )\right )}{24 f \left (\cot \left (\frac{1}{2} (e+f x)\right )+1\right ) \left (\csc ^2\left (\frac{1}{4} (e+f x)\right )-\sec ^2\left (\frac{1}{4} (e+f x)\right )\right )^3} \]
Antiderivative was successfully verified.
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Maple [A] time = 0.651, size = 196, normalized size = 1. \begin{align*} -{\frac{1+\sin \left ( fx+e \right ) }{24\, \left ( \sin \left ( fx+e \right ) \right ) ^{3}\cos \left ( fx+e \right ) f}\sqrt{-a \left ( -1+\sin \left ( fx+e \right ) \right ) } \left ( 96\,\sqrt{-a \left ( -1+\sin \left ( fx+e \right ) \right ) }{a}^{5/2} \left ( \sin \left ( fx+e \right ) \right ) ^{3}-16\, \left ( -a \left ( -1+\sin \left ( fx+e \right ) \right ) \right ) ^{3/2} \left ( \sin \left ( fx+e \right ) \right ) ^{3}{a}^{3/2}-111\,{\it Artanh} \left ({\frac{\sqrt{-a \left ( -1+\sin \left ( fx+e \right ) \right ) }}{\sqrt{a}}} \right ) \left ( \sin \left ( fx+e \right ) \right ) ^{3}{a}^{3}+15\,\sqrt{-a \left ( -1+\sin \left ( fx+e \right ) \right ) }{a}^{5/2}+8\, \left ( -a \left ( -1+\sin \left ( fx+e \right ) \right ) \right ) ^{3/2}{a}^{3/2}-15\, \left ( -a \left ( -1+\sin \left ( fx+e \right ) \right ) \right ) ^{5/2}\sqrt{a} \right ){a}^{-{\frac{3}{2}}}{\frac{1}{\sqrt{a+a\sin \left ( fx+e \right ) }}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int{\left (a \sin \left (f x + e\right ) + a\right )}^{\frac{3}{2}} \cot \left (f x + e\right )^{4}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 1.72276, size = 1123, normalized size = 5.7 \begin{align*} \frac{111 \,{\left (a \cos \left (f x + e\right )^{4} - 2 \, a \cos \left (f x + e\right )^{2} -{\left (a \cos \left (f x + e\right )^{3} + a \cos \left (f x + e\right )^{2} - a \cos \left (f x + e\right ) - a\right )} \sin \left (f x + e\right ) + a\right )} \sqrt{a} \log \left (\frac{a \cos \left (f x + e\right )^{3} - 7 \, a \cos \left (f x + e\right )^{2} + 4 \,{\left (\cos \left (f x + e\right )^{2} +{\left (\cos \left (f x + e\right ) + 3\right )} \sin \left (f x + e\right ) - 2 \, \cos \left (f x + e\right ) - 3\right )} \sqrt{a \sin \left (f x + e\right ) + a} \sqrt{a} - 9 \, a \cos \left (f x + e\right ) +{\left (a \cos \left (f x + e\right )^{2} + 8 \, a \cos \left (f x + e\right ) - a\right )} \sin \left (f x + e\right ) - a}{\cos \left (f x + e\right )^{3} + \cos \left (f x + e\right )^{2} +{\left (\cos \left (f x + e\right )^{2} - 1\right )} \sin \left (f x + e\right ) - \cos \left (f x + e\right ) - 1}\right ) - 4 \,{\left (16 \, a \cos \left (f x + e\right )^{5} - 64 \, a \cos \left (f x + e\right )^{4} - 17 \, a \cos \left (f x + e\right )^{3} + 165 \, a \cos \left (f x + e\right )^{2} + 9 \, a \cos \left (f x + e\right ) -{\left (16 \, a \cos \left (f x + e\right )^{4} + 80 \, a \cos \left (f x + e\right )^{3} + 63 \, a \cos \left (f x + e\right )^{2} - 102 \, a \cos \left (f x + e\right ) - 93 \, a\right )} \sin \left (f x + e\right ) - 93 \, a\right )} \sqrt{a \sin \left (f x + e\right ) + a}}{96 \,{\left (f \cos \left (f x + e\right )^{4} - 2 \, f \cos \left (f x + e\right )^{2} -{\left (f \cos \left (f x + e\right )^{3} + f \cos \left (f x + e\right )^{2} - f \cos \left (f x + e\right ) - f\right )} \sin \left (f x + e\right ) + f\right )}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [B] time = 3.10235, size = 1058, normalized size = 5.37 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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